x^2-7x+29=x-5

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Solution for x^2-7x+29=x-5 equation: 



x^2-7x+29=x-5

We move all terms to the left:

x^2-7x+29-(x-5)=0

We get rid of parentheses

x^2-7x-x+5+29=0

We add all the numbers together, and all the variables

x^2-8x+34=0

a = 1; b = -8; c = +34;
Δ = b2-4ac
Δ = -82-4·1·34
Δ = -72
Delta is less than zero, so there is no solution for the equation

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